Question

\(\dfrac{3}{5}-\dfrac{-7}{10}-\dfrac{13}{-20}\)

Answer 1

\(\dfrac{3}{5}-\dfrac{-7}{10}-\dfrac{13}{-20}=\dfrac{3}{5}+\dfrac{7}{10}+\dfrac{13}{20}=\dfrac{12}{20}+\dfrac{14}{20}+\dfrac{13}{20}=\dfrac{39}{20}\)

Answer 2

\(\dfrac{3}{5}+\dfrac{7}{10}+\dfrac{13}{20}=\dfrac{12}{20}+\dfrac{14}{20}+\dfrac{23}{20}=\dfrac{49}{20}\)

Answer 3

\(\dfrac{3}{5}+\dfrac{7}{10}+\dfrac{13}{20}=\dfrac{12+14+13}{20}=\dfrac{39}{20}\)

Answer 4

\(\dfrac{3}{5}-\dfrac{-7}{10}-\dfrac{13}{-20}\)

    \(\dfrac{3}{5}-\dfrac{-7}{10}-\dfrac{-13}{20}\)

⇔ \(\dfrac{12}{20}-\dfrac{-14}{20}-\dfrac{-13}{20}\)

⇔ \(\dfrac{12-\left(-14\right)-\left(-13\right)}{20}\)

⇔ \(\dfrac{39}{20}\)

Answer 5

\(\dfrac{3}{5}+\dfrac{7}{10}-\dfrac{13}{-20}=\dfrac{12}{20}+\dfrac{14}{20}+\dfrac{13}{20}=\dfrac{39}{20}\)

Answer 6

\(=\dfrac{39}{20}\)