Question

( \(\dfrac{3}{4}x\) + \(\dfrac{9}{16}\) ) x ( 1,5 + \(-\dfrac{3}{5}\) : x ) = 0

 

Answer 1

\(\left(\dfrac{3}{4}x+\dfrac{9}{16}\right)\left(1,5+\dfrac{-3}{5}:x\right)=0\)

=>\(\left[{}\begin{matrix}\dfrac{3}{4}x+\dfrac{9}{16}=0\\1,5+\dfrac{-3}{5}:x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{3}{4}x=-\dfrac{9}{16}\\-\dfrac{3}{5}:x=-1,5=-\dfrac{3}{2}\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=-\dfrac{9}{16}:\dfrac{3}{4}=-\dfrac{9}{16}\cdot\dfrac{4}{3}=-\dfrac{3}{4}\\x=\dfrac{3}{2}:\dfrac{3}{5}=\dfrac{5}{2}\end{matrix}\right.\)