Question

\(\dfrac{2x-1}{3}\) = \(\dfrac{27}{2x-1}\)

Answer 1

\(\dfrac{2x-1}{3}=\dfrac{27}{\left(2x-1\right)}\left(ĐKXĐ:x\ne\dfrac{1}{2}\right)\)

\(\Rightarrow\left(2x-1\right)^2=81\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-1=9\\2x-1=-9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\left(n\right)\\x=-4\left(n\right)\end{matrix}\right.\)