Câu hỏi của Khanh Tuệ

Question

(2x-1)$^3$=$\dfrac{-1}{27}$

Toru · Accepted Answer

$\left(2x-1\right)^3=\dfrac{-1}{27}$$\Rightarrow\left(2x-1\right)^3=\left(-\dfrac{1}{3}\right)^3$$\Rightarrow2x-1=-\dfrac{1}{3}$$\Rightarrow2x=-\dfrac{1}{3}+1$$\Rightarrow2x=\dfrac{2}{3}$$\Rightarrow x=\dfrac{2}{3}:2$$\Rightarrow x=\dfrac{1}{3}$Câu trả lời: $\left(2x-1\right)^3=\dfrac{-1}{27}$$\Rightarrow\left(2x-1\right)^3=\left(-\dfrac{1}{3}\right)^3$$\Rightarrow2x-1=-\dfrac{1}{3}$$\Rightarrow2x=-\dfrac{1}{3}+1$$\Rightarrow2x=\dfrac{2}{3}$$\Rightarrow x=\dfrac{2}{3}:2$$\Rightarrow x=\dfrac{1}{3}$

Võ Ngọc Phương · Answer

$\left(2x-1\right)^3=\dfrac{-1}{27}$$=>\left(2x-1\right)^3=\left(\dfrac{-1}{3}\right)^3$$=>2x-1=\dfrac{-1}{3}$$=>2x=\dfrac{-1}{3}+1=\dfrac{-1}{3}+\dfrac{3}{3}$$=>2x=\dfrac{2}{3}$$=>x=\dfrac{2}{3}:2=\dfrac{2}{3}.\dfrac{1}{2}$$=>x=\dfrac{2}{6}=\dfrac{1}{3}$$#Wendy.Dang$Câu trả lời: $\left(2x-1\right)^3=\dfrac{-1}{27}$$=>\left(2x-1\right)^3=\left(\dfrac{-1}{3}\right)^3$$=>2x-1=\dfrac{-1}{3}$$=>2x=\dfrac{-1}{3}+1=\dfrac{-1}{3}+\dfrac{3}{3}$$=>2x=\dfrac{2}{3}$$=>x=\dfrac{2}{3}:2=\dfrac{2}{3}.\dfrac{1}{2}$$=>x=\dfrac{2}{6}=\dfrac{1}{3}$$#Wendy.Dang$

Khoá học trên OLM (olm.vn)

Khoá học trên OLM (olm.vn)