\(\dfrac{2^7\cdot9^3}{6^3\cdot8^2}\\ =\dfrac{2^7\cdot\left(3^2\right)^3}{2^3\cdot3^3\cdot\left(2^3\right)^2}\\ =\dfrac{2^7\cdot3^6}{2^3\cdot3^3\cdot2^6}\\ =\dfrac{2^7\cdot3^6}{2^9\cdot3^3}\\ =\dfrac{3^3}{2^2}\\ =\dfrac{27}{4}\)
\(1-\dfrac{2}{3x5}-\dfrac{2}{5x7}-\dfrac{2}{7x9}-...-\dfrac{2}{19x21}\)
Tính tổng sau:
\(\dfrac{2}{3X5}+\dfrac{2}{5X7}+\dfrac{2}{7X9}+...+\dfrac{2}{19X21}\)
2^15x9^4/6^3x8^3
2^15x9^4 phần 6^3x8^3
\(\frac{2^7x9^2}{3^3x2^5}\) giúp mik
\(\dfrac{5}{6}.18\dfrac{2}{3}-\dfrac{5}{6}.6\dfrac{2}{3}\)
Tìm số nguyên x, biết:
a) \(-4\dfrac{3}{5}\). \(2\dfrac{4}{3}\) < x < \(-2\dfrac{3}{5}\) : \(1\dfrac{6}{15}\)
b) \(-4\dfrac{1}{3}\).(\(\dfrac{1}{2}\)-\(\dfrac{1}{6}\)) < x < - \(\dfrac{2}{3}\).(\(\dfrac{1}{3}\) - \(\dfrac{1}{2}\) - \(\dfrac{3}{4}\))
\(A=\dfrac{\left(17\dfrac{1}{4}-4\dfrac{3}{16}-13\dfrac{5}{6}\right).\left(\dfrac{-4}{7}\right)+6\dfrac{3}{4}}{\left(5\dfrac{2}{7}-\dfrac{16}{3}\right):\left(6\dfrac{2}{3}-4\dfrac{1}{2}\right)}\)
Bài 1: Tính một cách hợp lí
d) (\(^{2^2}\) : \(\dfrac{4}{3}\) - \(^{\dfrac{1}{2}}\) ) x \(\dfrac{6}{5}\) - 17
h) \(\dfrac{\left(-1\right)^3}{15}\) + \(\left(-\dfrac{2}{3}\right)^2\) : \(2\dfrac{2}{3}\) - \(\left|-\dfrac{5}{6}\right|\)
k) \(\dfrac{2.6^9-2^5.18^4}{2^2.6^8}\)
n) 3 - \(\left(-\dfrac{7}{8}\right)^0\) + \(\left(\dfrac{1}{2}\right)^3\) . 16
Mg giải gấp giúp mình ạ
\(\dfrac{4^{10}\times9^6+3^{12}\times8^5}{6^{13}\times4-2^{16}\times3^{12}}\)
\(\dfrac{2^4\times2^6}{\left(2^5\right)^2}-\dfrac{2^5\times15^3}{6^3\times10^2}\)
\(\dfrac{\left(-2\right)^{10}\times3^{31}+2^{40}\times\left(-3\right)^6}{\left(-2\right)^{11}\times\left(-3\right)^{31}+2^{41}\times3^6}\)
giải chi tiết giúp mình nhé
