Question

\(\dfrac{1}{2}x.\dfrac{1}{4}x^2.\dfrac{x^3}{8}.2y.4y-8y^3\)

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Answer 1

\(\dfrac{1}{2}x.\dfrac{1}{4}x^2.\dfrac{x^3}{8}.2y.4y-8y^3=x.x^2.x^3.y.y.\dfrac{2.4}{2.4.8}-8y^3\\ =x^6.y^2.\dfrac{1}{8}-8y^3\)

Answer 2

\(=\dfrac{1}{2}\cdot\dfrac{1}{4}\cdot\dfrac{1}{8}\cdot x^3\cdot x^3\cdot8y^2-8y^3\)

\(=\dfrac{1}{8}x^6y^2-8y^3\)