\(\dfrac{-2x+1}{-3}=\dfrac{x+2}{4}\)
\(\Rightarrow\dfrac{2x-1}{3}=\dfrac{x+2}{4}\)
\(\Rightarrow\dfrac{4\cdot\left(2x-1\right)}{3\cdot4}=\dfrac{3\cdot\left(x+2\right)}{3\cdot4}\)
\(\Rightarrow\dfrac{8x-4}{12}=\dfrac{3x+6}{12}\)
\(\Rightarrow8x-4=3x+6\)
\(\Rightarrow8x-3x=6+4\)
\(\Rightarrow5x=10\)
\(\Rightarrow x=\dfrac{10}{5}\)
\(\Rightarrow x=2\)
Vậy: x = 2
\(\dfrac{-2x+1}{-3}=\dfrac{x+2}{4}\)
\(\Rightarrow4\cdot\left(-2x+1\right)=-3\cdot\left(x+2\right)\)
\(\Rightarrow-8x+4=-3x-6\)
\(\Rightarrow-8x+3x=-6-4\)
\(\Rightarrow-5x=-10\)
\(\Rightarrow x=\dfrac{-10}{-5}=2\)
Vậy $x=2$.
