Question

(\(\dfrac{-1}{3}\))\(^3\) x (\(\dfrac{-3}{2}\))\(^2\) - \(\dfrac{-5}{12}\) x \(\dfrac{6}{10}\)

 

Answer 1

Ta có: \(\left(-\dfrac{1}{3}\right)^3\cdot\left(-\dfrac{3}{2}\right)^2-\dfrac{-5}{12}\cdot\dfrac{6}{10}\)

\(=\dfrac{-1}{27}\cdot\dfrac{9}{4}+\dfrac{5}{12}\cdot\dfrac{3}{5}\)

\(=\dfrac{-1}{12}+\dfrac{3}{12}\)

\(=\dfrac{2}{12}=\dfrac{1}{6}\)

Answer 2

\(\left(\dfrac{-1}{3}\right)^3.\left(\dfrac{-3}{2}\right)^2-\dfrac{-5}{12}.\dfrac{6}{10}\) 

\(=\dfrac{-1}{27}.\dfrac{9}{4}+\dfrac{1}{4}\) 

\(=\dfrac{-1}{12}+\dfrac{1}{4}\) 

\(=\dfrac{1}{6}\)