Question

ĐỀ BÀI 2: Đốt lưu huỳnh S + 02- SO2. nếu dùng 1,6 gam S . A/ Tính V khí S02=? B/ Tính V không khí =?

Answer 1

Ta có: \(n_S=\dfrac{1,6}{32}=0,05\left(mol\right)\)

\(PTHH:S+O_2\overset{t^o}{--->}SO_2\)

a. Theo PT: \(n_{SO_2}=n_S=0,05\left(mol\right)\)

\(\Rightarrow V_{SO_2}=0,05.22,4=1,12\left(lít\right)\)

b. Theo PT: \(n_{O_2}=n_S=0,05\left(mol\right)\)

\(\Rightarrow V_{O_2}=0,05.22,4=1,12\left(lít\right)\)

Mà: \(V_{O_2}=\dfrac{1}{5}.V_{kk}\)

\(\Leftrightarrow V_{kk}=V_{O_2}.5=1,12.5=5,6\left(lít\right)\)

Answer 2

\(n_S=n_{SO_2}=\dfrac{1.6}{32}=0.05\left(mol\right)\)

\(\Leftrightarrow V_{SO_2}=0.05\cdot22.4=1.12\left(lít\right)\)

\(V_{O_2}=32\cdot0.05=1.6\left(lít\right)\)