Question

Cho tỉ lệ thức \(\dfrac{a+b+c}{a+b-c}\) = \(\dfrac{a-b+c}{a-b-c}\) với b≠0 
Chứng minh rằng: c=0

Answer 1

Ta có: \(\dfrac{a+b+c}{a+b-c}=\dfrac{a-b+c}{a-b-c}\)

\(\Leftrightarrow a^2-\left(b+c\right)^2=a^2-\left(b-c\right)^2\)

\(\Leftrightarrow\left(b+c\right)^2-\left(b-c\right)^2=0\)

\(\Leftrightarrow-4bc=0\)

hay c=0