a: ĐKXĐ: x>=0; x<>1
b: \(A=\left(\dfrac{3}{\sqrt{x}-1}+\dfrac{\sqrt{x}-3}{x-1}\right):\dfrac{1}{\sqrt{x}-1}\)
\(=\dfrac{3\left(\sqrt{x}+1\right)+\sqrt{x}-3}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\cdot\dfrac{\sqrt{x}-1}{1}\)
\(=\dfrac{4\sqrt{x}}{\sqrt{x}+1}\)
A=3
=>\(4\sqrt{x}=3\sqrt{x}+3\)
=>\(\sqrt{x}=3\)
=>x=9(nhận)