2A = 2 + \(2^2+2^4+2^5+..........+2^{2015}+2^{2016}\)
\(2A-A=A=2^{2016}-1\)
vậy B = A
ủng hộ nha ai thấy đúng
\(A=1+2+2^2+...+2^{2015}\)
\(2A=2+2^2+2^3+...+2^{2016}\)
\(2A-A=\left(2+2^2+2^3+...+2^{2016}\right)-\left(1+2+2^2+...+2^{2015}\right)\)
\(A=2^{2016}-1\)
Vậy \(A=B=2^{2016}-1\)