Đổi 500ml=0,5l
\(n_{Ca}=\dfrac{12}{40}=0,3\left(g\right)\)
\(Ca+H_2SO_4\rightarrow CaSO_4+H_2\)
1...........1.............1............1....(mol)
0,3........0,3.......0,3............0,3..(mol)
\(C_{MH_2SO_4}=\dfrac{n}{Vdd}=\dfrac{0,3}{0,5}==0,6\left(M\right)\)