Question

Chia đa thức cho đa thức:
a) (2x⁴-3x³-3x²-2+6x) : (x²-2)
b) (5x³-3x²+7) : (x²+1)

Answer 1

a) \(\left(2x^4-3x^3-3x^2-2+6x\right):\left(x^2-2\right)=2\left(x^2-\dfrac{3}{2}x+\dfrac{1}{2}\right)\left(x^2-2\right):\left(x^2-2\right)=2x^2-3x+1\)

Answer 2

Answer 3

a: \(\dfrac{2x^4-3x^3-3x^2+6x-2}{x^2-2}\)

\(=\dfrac{2x^4-4x^2-3x^3+6x+x^2-2}{x^2-2}\)

\(=2x^2-3x+1\)

b: \(\dfrac{5x^3-3x^2+7}{x^2+1}\)

\(=\dfrac{5x^3+5x-3x^2-3-5x+10}{x^2+1}\)

\(=5x-3+\dfrac{-5x+10}{x^2+1}\)