Question

Câu 1: so sánh

A =  \(\dfrac{7^{2013}+1}{7^{2014}+1}\)  và  B = \(\dfrac{7^{2014}+1}{7^{2015}+1}\)

Answer 1

A<B

Answer 2

Answer 3

Tham khảo: https://hoc24.vn/cau-hoi/so-sanh-afrac720131720141va-bfrac720141720151.235038064198

Answer 4

Có A=\(\dfrac{7^{2013}+1}{7^{2014}+1}\)

=>7A=\(\dfrac{7^{2014}+7}{7^{2014}+1}\)

=>7A=\(\dfrac{\left(7^{2014}+1\right)+6}{7^{2014}+1}\)

=>7A=1+\(\dfrac{6}{7^{2014}+1}\)

Tg tự với B ta đc 7B=1+\(\dfrac{6}{7^{2015}+1}\)

Có \(\dfrac{6}{7^{2014}+1}>\dfrac{6}{7^{2015}+1}\)

=>\(1+\dfrac{6}{7^{2014}+1}>1+\dfrac{6}{7^{2015}+1}\)

=>7A > 7B

=>A>B