Câu 3:
\(\lim_{}\frac{6n+2}{n+5}\)
\(=\lim_{}\frac{6+\frac{2}{n}}{1+\frac{5}{n}}=\frac{6+0}{1+0}=\frac61=6\)
Câu 4:
\(\lim_{}\frac{1-2n}{\sqrt{n^2+1}}\)
\(=\lim_{}\frac{\frac{1}{n}-2}{\sqrt{1+\frac{1}{n^2}}}=\frac{0-2}{\sqrt{1+0}}=\frac{-2}{1}=-2\)
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