a, \(n_{C_2H_4}=\dfrac{0,112}{22,4}=0,005\left(mol\right)\)
PT: \(C_2H_4+Br_2\rightarrow C_2H_4Br_2\)
\(n_{Br_2}=n_{C_2H_4}=0,005\left(mol\right)\)
\(\Rightarrow V_{Br_2}=\dfrac{0,005}{0,1}=0,05\left(l\right)=50\left(ml\right)\)
b, \(n_{C_2H_2}=\dfrac{0,112}{22,4}=0,005\left(mol\right)\)
PT: \(C_2H_2+2Br_2\rightarrow C_2H_2Br_4\)
\(n_{Br_2}=2n_{C_2H_2}=0,01\left(mol\right)\)
\(\Rightarrow V_{Br_2}=\dfrac{0,01}{0,1}=0,1\left(l\right)=100\left(ml\right)\)