Question

các bạn giúp mình câu b ạ, mình cảm ơn

Answer 1

b) \(\dfrac{x^2+2\sqrt{2}x+2}{x^2-2}=\dfrac{\left(x+\sqrt{2}\right)^2}{\left(x-\sqrt{2}\right)\left(x+\sqrt{2}\right)}=\dfrac{x+\sqrt{2}}{x-\sqrt{2}}\)

Answer 2

a, \(\dfrac{x^2-5}{x+\sqrt{5}}=\dfrac{\left(x-\sqrt{5}\right)\left(x+\sqrt{5}\right)}{x+\sqrt{5}}=x-\sqrt{5}\)

Answer 3

Tk