a) Do AB//HD \(\Rightarrow\widehat{BAC}=\widehat{ACH}\) (2 góc so le trong)
\(\Rightarrow\widehat{ACH}=40^o\)
b) Do HD//EG \(\Rightarrow\widehat{HCE}=\widehat{CEG}\) (2 góc so le trong)
\(\widehat{HCE}=50^o\)
Mà: \(\widehat{ACE}=\widehat{ACH}+\widehat{HCE}\)
\(\Rightarrow\widehat{ACE}=40^o+50^o=90^o\)