Question

bài 3: tìm x

a)10+3(x-1)=10+6x

b) (x+1) (x-2)=0

Answer 1

a: =>10+3x-3=6x+10

=>3x-3=6x

=>-3x=3

=>x=-1

b: =>x+1=0 hoặc x-2=0

=>x=-1 hoặc x=2

Answer 2

a) \(10+3\left(x-1\right)=10+6x\)

\(\Rightarrow10+3x-3=10+6x\)

\(\Rightarrow3x-6x=10-10+3\)

\(\Rightarrow-3x=3\)

\(\Rightarrow x=-\dfrac{3}{3}\)

\(\Rightarrow x=-1\)

b) \(\left(x+1\right)\left(x-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x+1=0\\x-2=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)