a: =>5x=-60
hay x=-12
b: =>|2x-7|=11
=>2x-7=11 hoặc 2x-7=-11
=>2x=18 hoặc 2x=-4
=>x=9 hoặc x=-2
`a ) 4 x - 15 = -75 - x `
`=> 4x + x = -75 +15`
`<=> 5x = -60`
`=> x = -60/5 = -12`
Vậy `x=-12`
`b ) |2x -7| + 2 = 13`
`<=>|2x-7| = 13 - 2`
`<=>|2x-7| = 11`
`<=>`\(\left[{}\begin{matrix}2x-7=11\\2x-7=-11\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=18\\2x=-4\end{matrix}\right.\)
`<=>`\(\left[{}\begin{matrix}x=9\\x=-2\end{matrix}\right.\)
Vậy \(\left[{}\begin{matrix}x=9\\x=-2\end{matrix}\right.\)
\(4x-15=-75-x\)
\(4x+x=-75+15\)
\(5x=-60\)
`=>x=-12`
b) \(\left|2x-7\right|+2=13\)
\(\left|2x-7\right|=13-2=11\)
\(2x-7=11\)
`=>`\(\left[{}\begin{matrix}2x-7=11\\2x-7=-11\end{matrix}\right.\)
\(\left[{}\begin{matrix}2x=18\\2x=-4\end{matrix}\right.\)
\(x=\left[{}\begin{matrix}\dfrac{18}{2}=9\\-\dfrac{4}{2}=-2\end{matrix}\right.\)