a: Ta có: \(100-7\left(x-5\right)=58\)
\(\Leftrightarrow7\left(x-5\right)=42\)
\(\Leftrightarrow x-5=6\)
hay x=11
b: Ta có: \(12\left(x-1\right):3=4^3+2^3\)
\(\Leftrightarrow12\left(x-1\right)=216\)
\(\Leftrightarrow x-1=18\)
hay x=19
a) \(100-7.\left(x-5\right)=58\) b) \(12.\left(x-1\right):3=4^3+2^3\)
\(\Rightarrow7.\left(x-5\right)=42\) \(\Rightarrow12.\left(x-1\right):3=72\)
\(\Rightarrow x-5=6\) \(\Rightarrow12.\left(x-1\right)=216\)
\(\Rightarrow x=11\) \(\Rightarrow x-1=18\) \(\Rightarrow x=19\)
Vậy x = 11 Vậy x = 19
c) \(24+5x=7^5:7^3\) d)\(5.\left(x-1\right)-206=2^4.4\)
=> \(24+5x=49\) \(\Rightarrow5.\left(x-1\right)-206=64\)
\(\Rightarrow5x=25\) \(\Rightarrow5.\left(x-1\right)=270\)
\(\Rightarrow x=5\) \(\Rightarrow x-1=54\) \(\Rightarrow x=55\)
Vậy x = 5 Vậy x = 55
c: Ta có: \(5x+24=7^5:7^3\)
\(\Leftrightarrow5x=25\)
hay x=5
d: Ta có: \(5\left(x-1\right)-206=2^4\cdot4\)
\(\Leftrightarrow5\left(x-1\right)=64+206=270\)
\(\Leftrightarrow x-1=54\)
hay x=55
e: Ta có: \(5\left(x-4\right)^2-7=13\)
\(\Leftrightarrow5\left(x-4\right)^2=20\)
\(\Leftrightarrow\left(x-4\right)^2=4\)
\(\Leftrightarrow\left[{}\begin{matrix}x-4=2\\x-4=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\\x=2\end{matrix}\right.\)