x+13 chia hết cho x-3
=>x-3+16 chia hết cho x-3
=>16 chia hết cho x-3
=>\(x-3\in\left\{1;-1;2;-2;4;-4;8;-8;16;-16\right\}\)
=>\(x\in\left\{4;2;5;1;7;-1;11;-5;19;-13\right\}\)
x + 13 = x - 3 + 16
Để (x + 13) ⋮ (x - 3) thì 16 ⋮ (x - 3)
⇒ x - 3 ∈ Ư(16) = {-16; -8; -4; -2; -1; 1; 2; 4; 8; 16}
⇒ x ∈ {-13; -5; -1; 1; 2; 4; 5; 7; 11; 19}