Sửa đề: \(A=7^{2022}-7^{2021}+7^{2020}-7^{2019}+...+7^2-7\)
=>\(7A=7^{2023}-7^{2022}+7^{2021}-7^{2020}+...+7^3-7^2\)
=>\(8A=7^{2022}-7^{2021}+7^{2020}-7^{2019}+...+7^2-7+7^{2023}-7^{2022}+...+7^3-7^2\)
=>\(8A=7^{2023}-7\)
=>\(A=\dfrac{7^{2023}-7}{8}\)
tính :
A= 1+2-3-4+5+6-7-8+9+...+2018-2019-2020+2021-2022
1+2-3-4+5-6-7-8+...-2019-2020+2021+2022
1+2-3-4+5+6-7-8-....-2019-2020+2021+2022 help
B = 1 - 2 - 3 + 4 - 5 - 6 +7-8- 9 +...+ 2020 - 2021 - 2022
giúp mk, please :)
\(\dfrac{\dfrac{1}{6}+\dfrac{1}{7}+...+\dfrac{1}{2022}}{2017+\dfrac{2016}{6}+\dfrac{2015}{7}+...+\dfrac{1}{2021}}\)
A. \(\dfrac{1}{2020}\)
B. \(\dfrac{1}{2021}\)
C. \(\dfrac{1}{2019}\)
D. \(\dfrac{1}{2022}\)
chọn ra 3 ngừi nhanh nhứt:>>
1-2-3+4+5-6-7+8+...+2018-2019-2020+2021+2022-2023
Tính A = 7 mũ 2024 - 7 mũ 2023 + 7 mũ 2022 - 7 mũ 2021 + ... + 7 mũ 2 - 7
So sánh A và B
A=\(\dfrac{4-7^{2020}}{7^{2020}}\)+\(\dfrac{5+7^{2021}}{7^{2021}}\)
B=\(\dfrac{1}{7^{2019}}\)
2+3-4+5+6-7+8+9-10+...+2015+2016-2017+2018+2019-2020+2021+2022
