\(\left(3x+1\right)\left(x-2\right)=\left(x-2\right)\left(x-1\right)\\ \Leftrightarrow\left(x-2\right)\left(3x+1-x+1\right)=0\\ \Leftrightarrow\left(x-2\right)\left(2x+2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)
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