\(A=2xy-x^2-2yz+4y^2=2\cdot2\cdot\dfrac{1}{2}-2^2-2\cdot\dfrac{1}{2}\cdot\left(-1\right)+4\cdot\left(\dfrac{1}{2}\right)^2\)
\(=2-4+1+4\cdot\dfrac{1}{4}=-2+1+1=0\)
A = 2 (2 . 1/2 - 2) - 2 . 1/2 (-1 - 2 . 1/2)
A = 2 (1 - 2) - 1 (-1 - 1)
A = 2 . (-1) - 1 . (-2)
A = -2 + 2
A = 0
@Liz.Ald2094
=2⋅2⋅12−22−2⋅12⋅(−1)+4⋅(12)2A=2xy−x2−2yz+4y2=2⋅2⋅12−22−2⋅12⋅(−1)+4⋅(12)2