\(a.\)\(\frac{a}{b}=\frac{c}{d}\)=> \(ad=bc\)=> \(ad+ab=bc+ab\)=> a x ( b + d) = b x ( a + c )
=> \(\frac{a}{b}=\frac{a+c}{b+d}\left(đpcm\right)\)
\(b.\)\(\frac{a+b}{a-b}=\frac{c+a}{c-a}\)=> \(\frac{a+b}{c+a}=\frac{a-b}{c-a}\)( Áp dụng tính chất dãy tỉ số bằng nhau )
=>\(\frac{a}{b}=\frac{c}{a}\)=> \(a^2=bc\)( đpcm)
Bài 1 : a) CMR : nếu \(\frac{a}{b}=\frac{b}{c}=\frac{c}{a}\)thì \(a=b=c\)
b) CMR : nếu \(\frac{a}{b}=\frac{c}{d}=\frac{p}{q}\)thì \(\frac{ma+nc+ep}{mb+nd+eq}=\frac{a}{b}=\frac{c}{d}=\frac{p}{q}\)
Cho hai số hữu tỉ\(\frac{a}{b}\)và\(\frac{c}{d}\)(b>0,d>0).CMR
a,Nếu \(\frac{a}{b}< \frac{c}{d}\)thì ad<bc
b,Nếu ad<bc thì\(\frac{a}{b}< \frac{c}{d}\)
Cho a,b,c,d thỏa mãn $\frac{a}{b}$ =$\frac{b}{c}$ =$\frac{c}{d}$ =$\frac{d}{a}$
CMR:($\frac{2019b+2020c-2021d}{2019c+2020d-2021e}$)^3=$\frac{a^2}{bc}$
CMR nếu \(\frac{a}{b}=\frac{c}{d}\)thì \(\frac{a}{b}=\frac{c}{d}=\frac{a+c}{b+d}\)
a) Cho \(\frac{a}{b}\)= \(\frac{b}{c}\)=\(\frac{c}{d}\)
CMR:(\(\frac{a+b+c}{b+c+d}^{ }\))\(^3\)=\(\frac{a}{d}\)
b) Cho \(\frac{a1}{a2}\)=\(\frac{a2}{a3}\)=\(\frac{a3}{a4}\)=...=\(\frac{a2008}{a2009}\)
CMR:\(\frac{a1}{a2009}\)=(\(\frac{a1+a2+a3+...+a2008}{a2+a3+a4+...+a2009}\))\(^{2008}\)
c) Cho \(\frac{a}{2003}\)=\(\frac{b}{2004}\)=\(\frac{c}{2005}\)
CMR: 4(a-b)(b-c)=(c-a)\(^{^2}\)
bài 1: cho tỉ lệ thức \(\frac{a}{b}=\frac{c}{d}\)
a) CMR: (a+2c)(b+d)=(a+c)(b+2d) \(\left(b,d\ne0\right)\)
b) CMR: (a+c)(b-d)=ab-cd
c) CMR: \(\frac{a}{a-b}=\frac{c}{c-d}\left(a,b,c,d>0;a\ne b,c\ne d\right)\)
bài 2: cho \(\frac{a}{b}=\frac{b}{c}=\frac{c}{d}CMR:\left(\frac{a+b+c}{b+c+d}\right)^3=\frac{a}{d}\)
CMR
Nếu \(\frac{a}{b}< \frac{c}{d}\) (b,d>0) thì \(\frac{a}{b}< \frac{a+c}{b+d}< \frac{c}{d}\)
CMR nếu: (x + y - c - d)(a - b - c - d) = (a+b - c - d)(a-b+c+d) thì \(\frac{a+b}{a-b}=\frac{c-d}{c+d}\)
CMR nếu \(\frac{a^2+b^2}{c^2+d^2}=\frac{ab}{cd}\)(a,b,c,d khác 0). CMR \(\frac{a}{b}=\frac{c}{d}\)hoặc \(\frac{a}{b}=\frac{d}{c}\)
