\(\left[\left(8x-12\right):4\right].3^3=3^6\)
\(\Leftrightarrow\left(8x-12\right):4=3^3\)
\(\Leftrightarrow2x-3=27\Leftrightarrow2x=30\Leftrightarrow x=15\)
[(8x-12):4].33=36
(8x-12):4=33
(8x-12):4=27
⇒8x-12=108
⇒8x=120
⇒x=15
\(\dfrac{8x-12}{4}.3^3=3^6\)
\(\Rightarrow\dfrac{8x-12}{4}=3^3\)
\(\Rightarrow8x-12=108\)
\(\Rightarrow8x=120\)
\(\Rightarrow x=15\)
( ( 8x -12 ) :4).33= 36
(8x-12) : 4= 33
(8x - 12) : 4= 27
=>8x -12 = 108
=>8x = 120
=>x= 15
Ta có: \(\left[\left(8x-12\right):4\right]\cdot3^3=3^6\)
\(\Leftrightarrow2x-3=27\)
hay x=15