\(=\dfrac{8}{3}+\dfrac{3}{5}=\dfrac{40+9}{15}=\dfrac{49}{15}\)
\(\dfrac{8}{3}+\dfrac{1}{3}x\dfrac{9}{5}=\dfrac{8}{3}+\dfrac{9}{15}=\dfrac{8}{3}+\dfrac{3}{5}=\dfrac{40}{15}+\dfrac{9}{15}=\dfrac{49}{15}\)
\(\dfrac{8}{3}\)+\(\dfrac{1}{3}\).\(\dfrac{9}{5}\)=\(\dfrac{8}{3}\)+\(\dfrac{9}{15}\)
=\(\dfrac{40}{15}\)+\(\dfrac{9}{15}\)
=\(\dfrac{40+9}{15}\)
=\(\dfrac{49}{15}\)