Question

7x (16x²-1)=0

Answer 1

\(7x\left(16x^2-1\right)=0\)

\(\Leftrightarrow7x\left(4x-1\right)\left(4x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{4}\\x=-\dfrac{1}{4}\end{matrix}\right.\)

Answer 2

16x^2-1=0

16 x^2=1

x^2=1/16

x=1/4 

Answer 3

\(\Rightarrow7x\left(4x-1\right)\left(4x+1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{4}\\x=-\dfrac{1}{4}\end{matrix}\right.\)

Answer 4

112x² - 7 = 0

x = 0,25