Question

7+ 2\(\sqrt{x}\) - \(x\) = (2 + \(\sqrt{x}\)).\(\sqrt{7 - x}\)

Answer 1

=>\(7-x+2\sqrt{x}=\left(2+\sqrt{x}\right)\sqrt{7-x}\)

\(\Leftrightarrow\sqrt{\left(7-x\right)^2}+2\sqrt{x}=2\sqrt{7-x}+\sqrt{x}\cdot\sqrt{7-x}\)

=>\(\sqrt{7-x}\cdot\left(\sqrt{7-x}-\sqrt{x}\right)=2\left(\sqrt{7-x}-\sqrt{x}\right)\)

=>7-x=4

=>x=3