\(6\left(x-2^3\right)+40=100\\ \Rightarrow6\left(x-8\right)=60\\ \Rightarrow x-8=10\\ \Rightarrow x=18\)
6(x - 23) + 40 = 100
<=> 6(x - 23) = 60
<=> x - 23 = 10
<=> x = 23 + 10
<=> x = 18
\(\Leftrightarrow x-8=10\)
hay x=18
\(6\left(x-2^3\right)+40=100\\ \Rightarrow6\left(x-8\right)=60\\ \Rightarrow x-8=10\\ \Rightarrow x=18\)
6(x - 23) + 40 = 100
<=> 6(x - 23) = 60
<=> x - 23 = 10
<=> x = 23 + 10
<=> x = 18
\(\Leftrightarrow x-8=10\)
hay x=18
a. 6(x+2^3)+40=100
b. 2^2(x+3^2)-5=55
1, (2+4+6+...+100)
2, 10-(3-x)=-10+17
3, 17-(3+x)=2-(7-8)
4, (5+x)-(15-31)=-20
5, 17-(3+x)+15-3=2
6, (41-x)-(13-17)=40-50
7, -(52-x)+(40-42)=-57+13
Tìm X
e) – 40 – (– 3 – 33) + (40 – x) = – (– 47) f) x(3x – 9). (121 – x2) = 0
g) – 62 – (38 + x) + 2x = – 100 h) (x + 1)2.(x2 + 1) = 0
i) (x – 12) – (2x + 31) = 6 k) 17/ (x + 3)3 : 3 – 1 = – 10
Tìm X
e) – 40 – (– 3 – 33) + (40 – x) = – (– 47) f) x(3x – 9). (121 – x2) = 0
g) – 62 – (38 + x) + 2x = – 100 h) (x + 1)2.(x2 + 1) = 0
i) (x – 12) – (2x + 31) = 6 k) 17/ (x + 3)3 : 3 – 1 = – 10
Tìm X
e) – 40 – (– 3 – 33) + (40 – x) = – (– 47) f) x(3x – 9). (121 – x2) = 0
g) – 62 – (38 + x) + 2x = – 100 h) (x + 1)2.(x2 + 1) = 0
i) (x – 12) – (2x + 31) = 6 k) 17/ (x + 3)3 : 3 – 1 = – 10
Bài 2.Tìm x
d,155-10(x+1)=55
e,6(x+2^3)+40=100
f,2^2(x+3^2)-5=55
7 [ x + 5 ] - 20 = 190 155 - 10 [ x + 1 ]= 55
6 [ x + 2 mũ 3 ] + 40 = 100 15x - 133 = 17
90 [ x + 2 ] = 45 14x + 54= 82
17x - 20 =14
Tìm số tự nhiên x biết
a) 2 mũ 2 ( x + 3 mũ 2 ) - 5 = 55
b) 7 ( x + 5 mũ 2 ) - 20 = 190
c) 6 ( x + 2 mũ 3 ) + 40 = 100
Tìm x biết:
a, 5(x – 7) = 0
b, 95 – 5(x+2) = 45
c, 6 2 x + 2 3 + 40 = 100
d, 3(3x+9)+6 = 96
e, 2 6 + 5 + x = 3 4