Question

6/13:(0,5+x)=15/39

Answer 1

\(\dfrac{6}{13}:\left(0,5+x\right)=\dfrac{15}{39}\)

\(\dfrac{6}{13}:\left(0,5+x\right)=\dfrac{5}{13}\)

\(0,5+x=\dfrac{6}{13}:\dfrac{5}{13}\)

\(0,5+x=\dfrac{6}{13}\cdot\dfrac{13}{5}\)

\(0,5+x=\dfrac{6}{5}\)

\(x=\dfrac{6}{5}-0,5\)

\(x=\dfrac{12}{10}-\dfrac{5}{10}\)

\(x=\dfrac{7}{10}\)

Answer 2

\(\dfrac{6}{13}:\left(x+0.5\right)=\dfrac{15}{39}\)

=>\(x+0.5=\dfrac{6}{13}:\dfrac{15}{39}=\dfrac{6}{13}:\dfrac{5}{13}=1.2\)

=>x=0,7

Answer 3

\(\dfrac{6}{13}:\left(0,5+x\right)=\dfrac{15}{39}\\ \Rightarrow\dfrac{6}{13}:\left(\dfrac{1}{2}+x\right)=\dfrac{15}{39}\\ \Rightarrow\dfrac{1}{2}+x=\dfrac{6}{13}:\dfrac{15}{39}\\ \Rightarrow\dfrac{1}{2}+x=\dfrac{6}{13}\times\dfrac{39}{15}\\ \Rightarrow\dfrac{1}{2}+x=\dfrac{6}{5}\\ \Rightarrow x=\dfrac{6}{5}-\dfrac{1}{2}=\dfrac{6\times2-5}{10}=\dfrac{7}{10}\)

Answer 4

\(\dfrac{6}{13}\) : ( 0,5 + \(x\) ) = \(\dfrac{15}{39}\)

​\(\dfrac{6}{13}\) : ( 0,5 + \(x\) )​ = \(\dfrac{5}{13}\)

0,5 + \(x\) = \(\dfrac{6}{13}\) : \(\dfrac{5}{13}\)

0,5 + \(x\) = \(\dfrac{6}{13}\) \(\cdot\) \(\dfrac{13}{5}\)

0,5 + \(x\) =       \(\dfrac{6}{5}\)

\(x\) = \(\dfrac{6}{5}\) - 0,5

\(x\) = 1,2 - 0,5

\(x\) =       0,7