Question

(-5^5+2^4-1/3x^3):(_1/2x^3)

Answer 1

Sửa đề: \(\left(-5x^5+2x^4-\dfrac{1}{3}x^3\right):\left(-\dfrac{1}{2}x^3\right)\)

\(=5x^5:\dfrac{1}{2}x^3-2x^4:\dfrac{1}{2}x^3+\dfrac{1}{3}x^3:\dfrac{1}{2}x^3\)

\(=10x^2-4x+\dfrac{2}{3}\)

Answer 2

`#AnChii`

`(-5x^5 + 2x^4 - 1/3 x^3) : (-1/2 x^3)`

`= (-5x^5 : -1/2 x^3) + (2x^4 : -1/2 x^3) - (1/3 x^3 : -1/2 x^3)`

`= (-5 : -1/2). (x^5 : x^3) + (2 : -1/2) .( x^4 : x^3) - (1/3 : -1/2) . (x^3 : x^3)`

`= 10x^2 - 4x + 2/3`