`(5 + 10 + 15 + ... + 100) : x = 70`
Ta có:
`5+10+15+20+...+95+100`
`=100+(5+95)+(10+90)+...+(45+55) +50`
`=100 + 9 . 100 + 50`
`=150 + 900`
`=1050`
`=>` `1050 : x = 70`
`x = 1050 : 70`
`x = 15`
Vậy `x = 15`
{[100-5):5+1]x(100+5):2} : x = 70
{20x105:2} : x = 70
{105x10} : x =70
1050 : x= 70
x=15
x=1155:70
x=15