\(4x\left(x-3\right)+x^2=4x^2-12x+x^2=5x^2-12x\)
\(4x\left(x-3\right)+x^2=4x^2-12x+x^2=5x^2-12x\)
4x2 + 4x + 1 =x2
(x+2) (3-4x)=x2+4x+6
x+3/x+1 + x-2/x =2
Giải các phương trình sau:
g/ x(x + 3)(x – 3) – (x + 2)(x2 – 2x + 4) = 0
h/ (3x – 1)(x2 + 2) = (3x – 1)(7x – 10)
i/ (x + 2)(3 – 4x) = x2 + 4x + 4
k/ x(2x – 7) – 4x + 14 = 0
m/ x2 + 6x – 16 = 0
n/ 2x2 + 5x – 3 = 0
a. (2x - 5)2 + (4x - 10)(2 + x) + x2 + 4x + 4 = 0
b. ( 3 – x2 + 5x )( x2 – 5x + 3) = 9
Tim x, biết:
Câu 1. x2 + 4x + 4 = 9
Câu 2. 4x2 + 4x + 1 = 4
Câu 3. x2 + 2x - 8 =0
Câu 4. x2 + 4x - 12 = 0
Bài 1:Phân tích đa thức thành nhân tử:
a) x3y+x-y-1
b) x2.(x-2)+4.(2-x)
c) x3-x2-20x
d) (x2+1)2-(x+1)2
e) 6x2-7x+2
f) x4+8x2+12
g) (x3+x+1).(x3+x)-2
h) (x+1).(x+2).(x+3).(x+4)-1
i) -(x2+2)2+4x.(x2+2)-3x2
j) -(x2+2)2+4x.(x2+2).3x2
k) -(x2+2)2+4x.(x2+2)+3x2
l) 81x4+4y4
Giúp với ạa
4x(x -1) - 3(x2 - 5) - x2 = (x - 3) - (x-4)
Tìm giá trị nhỏ nhất
a) x2 + x + 1
b)4x2+4x-5
c)(x-3)(x+5) + 4
d)x2 - 4x + y2 - 8y + 6
a, x2 - 4x = 0 b, (2x + 1)2 - 4x (x + 3) = 9
c, x2 -12x = -36
(x+4)(x2-4x+16)
(x-3y)(x2+3xy+9y2)
(x2-\(\dfrac{1}{3}\))(x4+\(\dfrac{1}{3}\)x2+\(\dfrac{1}{9}\))
Tìm x :
b )(x-1) . ( x2 +x +1) -x.(x-3) . (x+3 )=8
c)( X2 + 2 ) . (x-4 ) - ( X+2 ). ( x2 +4x +4=-16