Question

4x²-8x=0

Answer 1

\(4x^2-8x=0\)

\(\Leftrightarrow4x\left(x-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}4x=0\\x-2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

Vậy S = {0; 2}

Answer 2

\(4x^2-8x=0\)

\(\Leftrightarrow4x\left(x-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

Answer 3

\(\Leftrightarrow4x\left(x-2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

Answer 4

4x^2-8x=0

4x ( x-2)=0

-> 4x=0 hoặc x-2 = 0

-> x=0; x=2

Vậy x ={0; 2}

Answer 5

Ta có: \(4x^2-8x=0\)

\(\Leftrightarrow4x\left(x-2\right)=0\)

mà 4>0

nên x(x-2)=0

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

vậy: S={0;2}