\(4\cdot2^x-3=1\)
\(4\cdot2^x=4\)
\(2^x=1\)
\(2^x=2^0\)
\(x=0\)
\(4
.
2^x-3=1\)
\(\Rightarrow
4.2^x=4\)
\(\Rightarrow
2^x=1=1^0\)
Vậy \(x=0\)
4.2x - 3 = 1
4.2x = 1 + 3
4.2x = 4
2x = 4 : 4
2x = 1
2x = 20
=> x = 0
vậy x = 0
4⋅2x−3=14⋅2x−3=1
4⋅2x=44⋅2x=4
2x=12x=1
2x=202x=20
x=0