Question

(3x+6) (x-4)=0

Answer 1

\(\left(3x+6\right)\left(x-4\right)=0\)

\(+,TH1:3x+6=0\)

\(\Rightarrow3x=-6\)

\(\Rightarrow x=\dfrac{-6}{3}=-2\)

\(+,TH2:x-4=0\)

\(\Rightarrow x=4\)
Vậy: \(x\in\left\{-2;4\right\}\)

#\(Toru\)

Answer 2

(3x+6) (x-4)=0

=>3x+6=0 hoặc x-4 =0

=> 3x=-6             x=4

=> x=-2              x=4

vậy x∈{-2;4}

Answer 3

(3x + 6)(x - 4) = 0

3x + 6 = 0 hoặc x - 4 = 0

*) 3x + 6 = 0

3x = -6

x = -6/3

x = -2

*) x - 4 = 0

x = 4

Vậy x = -2; x = 4