Question

\(3x^2-2x=5\)

Answer 1

\(3x^2-2x=5\\ \Leftrightarrow3x^2-2x-5=0\\ \Leftrightarrow\left(3x^2+3x\right)-\left(5x+5\right)=0\\ \Leftrightarrow3x\left(x+1\right)-5\left(x+1\right)=0\\ \Leftrightarrow\left(x+1\right)\left(3x-5\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x+1=0\\3x-5=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{5}{3}\end{matrix}\right.\)

Answer 2

\(\Leftrightarrow3x^2-2x-5=0\)

\(\Leftrightarrow3x^2-5x+3x-5=0\)

=>(3x-5)(x+1)=0

=>x=-1 hoặc x=5/3

Answer 3

\(3x^2-2x-5=0\\ =>3x^2+3x-5x-5=0\\ =>3x\left(x+1\right)-5\left(x+1\right)=0\\ =>\left(3x-5\right)\left(x+1\right)=0\\ =>x=\dfrac{5}{3};x=-1\)

Answer 4

\(\Leftrightarrow3x^2-2x-5=0\)

\(\Leftrightarrow3x^2+3x-5x-5=0\)

\(\Leftrightarrow3x\left(x+1\right)-5\left(x+1\right)=0\)

\(\Leftrightarrow\left(x+1\right)\left(3x-5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+1=0\\3x-5=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{5}{3}\end{matrix}\right.\)

Answer 5

x = -1 hoặc 5/3

Answer 6

=>x.(3x-2)=5

=> x=0 hoặc 3x-2=5

=> x=0  hoặc   x=7/3