Question

\(3x-\dfrac{1}{3}-5x=\dfrac{3}{2}-4\)

Answer 1

\(-2x-\dfrac{1}{3}=\dfrac{3-4.2}{2}\\ -2x-\dfrac{1}{3}=-\dfrac{5}{2}\\ -2x=-\dfrac{5}{2}+\dfrac{1}{3}\\ -2x=\dfrac{-5.3+2}{6}\\ -2x=-\dfrac{13}{6}\\ x=\left(-\dfrac{13}{6}\right):\left(-2\right)\\ x=\dfrac{13}{12}\)

Answer 2

<=>-2x=\(\dfrac{1}{3}+\dfrac{3}{2}-4\)

<=>-2x=\(\dfrac{-13}{6}\)

<=>x=\(\dfrac{13}{12}\)