Question

3^x-1 +3^x +3^x+1 = 39

Answer 1

3ˣ⁻¹ + 3ˣ + 3ˣ⁺¹ = 39

3ˣ⁻¹.(1 + 3 + 3²) = 39

3ˣ⁻¹.13 = 39

3ˣ⁻¹ = 39 : 13

3ˣ⁻¹ = 3

x - 1 = 1

x = 1 + 1

x = 2

Answer 2

\(3^{x-1}+3^x+3^{x+1}=39\)

\(=>3^x:3+3^x+3^x.3=39\)

\(=>3^x.\dfrac{1}{3}+3^x+3^x.3=39\)

\(=>3^x.\left(\dfrac{1}{3}+1+3\right)=39\)

\(=>3^x.\dfrac{13}{3}=39\)

\(=>3^x=39:\dfrac{13}{3}=39.\dfrac{3}{13}\)

\(=>3^x=9=3^2\)

\(=>x=2\)