`(3-x)^3=-27/64`
`(3-x)^3=(-3/4)^3`
`3-x=-3/4`
`x=3+3/4`
`x=15/4`
Vậy `x=15/4`
\(\left(3-x\right)^3=-\dfrac{27}{64}\\ \left(3-x\right)^3=\left(-\dfrac{3}{4}\right)^3\\3-x=-\dfrac{3}{4}\\ x=3+\dfrac{3}{4}\\ x=\dfrac{15}{4}\)
Vậy: ...
`(3-x)^3=-27/64`
`(3-x)^3=(-3/4)^3`
`3-x=-3/4`
`x=3+3/4`
`x=15/4`
Vậy `x=15/4`
\(\left(3-x\right)^3=-\dfrac{27}{64}\\ \left(3-x\right)^3=\left(-\dfrac{3}{4}\right)^3\\3-x=-\dfrac{3}{4}\\ x=3+\dfrac{3}{4}\\ x=\dfrac{15}{4}\)
Vậy: ...
\(\left(3-x\right)^3=-\dfrac{27}{64};\left(x-5\right)^3=\dfrac{1}{-27};\left(x-\dfrac{1}{2}\right)^3=\dfrac{27}{8};\left(2x-1\right)^2=\dfrac{1}{4};\left(2-3x\right)^2=\dfrac{9}{4};\left(1-\dfrac{2}{3}\right)^2=\dfrac{4}{9}\)
17)\(\dfrac{\left(x+3\right)^5}{\left(x+3\right)^2}=\dfrac{64}{27}\)
(x3-\(\dfrac{27}{64}\)).(\(\sqrt{x}\)-3)=0
Tìm x( giải thích giúp mình với nhé)
\(\dfrac{45^{10}\cdot5^{20}}{75^{15}}\)
\(\dfrac{6^6+6^3+3^3+3^6}{-73}\)
\(\dfrac{27^7+3^{15}}{9^9-27}\)
\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}\)
In the figure below, x = Câu 2 Find the measure of angle J if \widehat{K}=29^o K =29 o and angle J and K are supplementary. Answer: \widehat{J}= J = ^o o . Câu 3 In the figure below, x = Câu 4 In the figure below, x = Câu 5 Solve: |2x-3|-4=3∣2x−3∣−4=3, where xx is a negative number. Answer: x=x= Câu 6 Calculate: 9+|-6|:1^2 =9+∣−6∣:1 2 = Câu 7 Compare: \dfrac{36}{27} 27 36 \dfrac{4}{3} 3 4 Câu 8 Find the negative number yy such that |y+\dfrac{7}{2}|-\dfrac{1}{2}=4∣y+ 2 7 ∣− 2 1 =4. Answer: y=y= Câu 9 Find xx such that \dfrac{32}{2^x}=2 2 x 32 =2. Answer: x=x= Câu 10 Find nn such that \dfrac{(-4)^n}{64}=-16 64 (−4) n =−16. Answer: n=n= Cần gấp nhé
tính hợp lí
a,\(\dfrac{27}{2}\) x 7,5 + \(\dfrac{27}{2}\) x 2,5 -150
b,3\(^3\)x \(\dfrac{18}{5}\) - 3\(^3\) x 2\(\dfrac{2}{5}\) - 3\(^3\) x \(\dfrac{6}{5}\)
a) x^3/8 = y^3/64 = z^3/216 và x^2 + y^2 + z^2 = 14
b) x^3/8 = y^3/27 = z^3/64 và x^2 + 2y^2 - 3z^2 = -650
Giúp mik với
Tìm x,y biết \(\dfrac{x^3+y^3}{6}=\dfrac{x^3-2y^3}{4}\) và \(x^6.y^6=64\)
Tìm x:
\(a\)) \(\dfrac{2}{3}+\left(x-\dfrac{1}{2}\right)^3=\dfrac{19}{27}\)
\(b\)) \(\left(\dfrac{3}{2}\right)^{2x-1}:\left(\dfrac{27}{8}\right)^3=\dfrac{81}{16}\)
\(c\)) \(\dfrac{1}{2}.2^x+4.2^x=9.2^5\)
\(d\)) \(\text{12 - (2x +1)}^2=-69\)
\(\dfrac{3^{x-5}+3^{x-4}+3^{x-3}}{13}=^{\dfrac{27}{3^x}}\)