\(3\left(1-4x\right)\left(x-1\right)+4\left(3x-2\right)\left(x+3\right)=-27\)
\(\Leftrightarrow3\left(-1-4x^2+5x\right)+4\left(3x^2+7x-6\right)=-27\)
\(\Leftrightarrow-12x^2+15x-3+12x^2+28x-24=-27\)
\(\Leftrightarrow43x-27=-27\Leftrightarrow x=0\)
\(3\left(1-4x\right)\left(x-1\right)+4\left(3x-2\right)\left(x+3\right)=-27\)
\(\Leftrightarrow\left(3-12x\right)\left(x-1\right)+\left(12x-8\right)\left(x+3\right)=-27\)
\(\Leftrightarrow3x-3-12x^2+12x+12x^2+36x-8x-24+27=0\)
\(\Leftrightarrow43x=0\)
\(\Leftrightarrow x=0\)
#H
Trả lời:
3( 1 - 4x )( x - 1 ) + 4( 3x - 2 )( x + 3 ) = - 27
<=> ( 3 - 12x )( x - 1 ) + ( 12x - 8 )( x + 3 ) = - 27
<=> 3x - 3 - 12x2 + 12x + 12x2 + 36x - 8x - 24 = - 27
<=> 43x - 27 = - 27
<=> 43x = 0
<=> x = 0
Vậy x = 0 là nghiệm của pt.
