Question

2*(x+3)^2=2*(x-2)^2

Answer 1

\(2\left(x+3\right)^2=2\left(x-2\right)^2\)

=>\(\left(x+3\right)^2=\left(x-2\right)^2\)

=>\(x^2+6x+9=x^2-4x+4\)

=>\(6x+9=-4x+4\)

=>10x=-5

=>x=-1/2

Answer 2

\(2\left(x+3\right)^2=2\left(x-2\right)^2\\ \Leftrightarrow\left(x+3\right)^2=\dfrac{2\left(x-2\right)^2}{2}\\ \Leftrightarrow\left(x+3\right)^2-\left(x-2\right)^2=0\\ \Leftrightarrow\left(x+3-x+2\right)\left(x+3+x-2\right)=0\\ \Leftrightarrow5\left(2x+1\right)=0\\ \Leftrightarrow2x+1=0\\ \Leftrightarrow2x=-1\\ \Leftrightarrow x=-\dfrac{1}{2}\)

Vậy: ...