=>2x(x^2-11x+18)=0
=>x(x-2)(x-9)=0
=>\(x\in\left\{0;2;9\right\}\)
Tìm x:
a) x^2 - 25x=0
b) (x-3)^2 - 36x^2=0
c) 2x(3-x)+2x^2=12
d) x(x-2)-x+2=0
bài 7 tìm x
1,x(x+3)-5(x+3)=0 2,5x(x-1)=x-1
3,(x+1)=(x+1)\(^2\) 4,x(2x-3)-2(3-2x)=0
5,\(\left(x-2\right)^2-4=0\) 6,\(36x^2=49\)
7,\(2x\left(x-6\right)-x+6=0\) 8,\(3x\left(2x-1\right)-24x+12=0\)
9,\(x^2-6x+8=0\) 10,\(x^2+2x-15=0\)
Tìm x
a) (2x-5)2-(5+2x)=0
b) 27x3-54x2+36x=0
c)(x3+8)-(x+2)(x-4)=0
d)x6-1=0
2x2+22x-x-22=0
Tìm x thỏa mãn:
a) ( 2 x - 5 ) 2 - ( 5 + 2 x ) 2 = 0; b) 27 x 3 - 54 x 2 + 36x = 8.
tìm x:
a. x.(x+3)-x2+15=0
b. (2x-1)(x+3) - x(2x-6) =15
c. x3 -36x = 0
d. 6x2 + 6x =x2+2x+1
e. x(3x+1)=1-9x2
a) 2(x-1)2+(x+3)2=3(x-2)(x+1)
b) (x-1)2+(x-2)2=2(x+4)2-(22x+27)
c) x3-5x2+12x-5=0
d) (2x-1)2+(x+3)2-5(x+7) (x-7)=0
Tìm x, biết:
a.(x-3).(x+3)=(x-5)^2
b.(2x+1)^2-4x.(x-1)=17
c.(3x-2).(3x+2)-9.(x-1).x=0
d.(3-x)^3-(x+3)^3=36x^2-54x
e.x^3-6x^2+12x-8=27
(6x-1/3) (36x^2 +2x + 1/9)
