=>(2x-4)^10*[(2x-4)^200-1]=0
=>(2x-4)(2x-5)(2x-6)=0
hay \(x\in\left\{2;\dfrac{5}{2};3\right\}\)
(2x - 4)²¹⁰ = (2x - 4)¹⁰
(2x - 4)²¹⁰ - (2x - 4)¹⁰ = 0
(2x - 4)¹⁰.[(2x - 4)²⁰⁰ - 1] = 0
(2x - 4)¹⁰ = 0 hoặc (2x - 4)²⁰⁰ - 1 = 0
*) (2x - 4)¹⁰ = 0
2x - 4 = 0
2x = 4
x = 2
*) (2x - 4)²⁰⁰ - 1 = 0
(2x - 4)²⁰⁰ = 1
2x - 4 = 1 hoặc 2x - 4 = -1
**) 2x - 4 = 1
2x = 1 + 4
2x = 5
x = 5/2
**) 2x - 4 = -1
2x = -1 + 4
2x = 3
x = 3/2
Vậy x = 3/2; x = 2; x = 5/2