\(\dfrac{2x-3}{5}-x-1=\dfrac{x+2}{4}-\dfrac{x+1}{2}\)
=>\(\dfrac{4\left(2x-3\right)}{20}+\dfrac{20\left(-x-1\right)}{20}=\dfrac{5\left(x+2\right)-10\left(x+1\right)}{20}\)
=>\(4\left(2x-3\right)-20x-20=5x+10-10x-10\)
=>8x-12-20x-20=-5x
=>-12x-32=-5x
=>12x+32=5x
=>7x=-32
=>\(x=-\dfrac{32}{7}\)