\(\left(2x-1\right)^3=\dfrac{8}{27}\)
\(\Rightarrow\left(2x-1\right)^3=\left(\dfrac{2}{3}\right)^3\)
\(\Rightarrow2x-1=\dfrac{2}{3}\)
\(\Rightarrow2x=\dfrac{2}{3}+1\)
\(\Rightarrow2x=\dfrac{5}{3}\)
\(\Rightarrow x=\dfrac{5}{3}:2=\dfrac{5}{6}\)
\(\left(2x-1\right)^3=\dfrac{8}{27}\)
\(\Rightarrow\left(2x-1\right)^3=\left(\dfrac{2}{3}\right)^3\)
\(\Rightarrow2x-1=\dfrac{2}{3}\)
\(\Rightarrow2x=\dfrac{2}{3}+1\)
\(\Rightarrow2x=\dfrac{5}{3}\)
\(\Rightarrow x=\dfrac{5}{3}:2=\dfrac{5}{6}\)
Tìm x:
\(a\)) \(\dfrac{2}{3}+\left(x-\dfrac{1}{2}\right)^3=\dfrac{19}{27}\)
\(b\)) \(\left(\dfrac{3}{2}\right)^{2x-1}:\left(\dfrac{27}{8}\right)^3=\dfrac{81}{16}\)
\(c\)) \(\dfrac{1}{2}.2^x+4.2^x=9.2^5\)
\(d\)) \(\text{12 - (2x +1)}^2=-69\)
\(\left(3-x\right)^3=-\dfrac{27}{64};\left(x-5\right)^3=\dfrac{1}{-27};\left(x-\dfrac{1}{2}\right)^3=\dfrac{27}{8};\left(2x-1\right)^2=\dfrac{1}{4};\left(2-3x\right)^2=\dfrac{9}{4};\left(1-\dfrac{2}{3}\right)^2=\dfrac{4}{9}\)
tìm x
a) x: 27=3,6
b)\(\dfrac{2x+1}{-27}\) =\(\dfrac{-3}{2x+1}\)
1, 3x = \(\dfrac{9^8}{27^3.81^2}\)
2,\(\dfrac{2^{4-x}}{16^5}\)= 326
3,\(\dfrac{2^{2x-3}}{4^{10}}\) = 83. 165
giúp em nhanh với ạ . mik đang gấp .
\(\dfrac{1}{3}\)x(2x-\(\dfrac{1}{3}\))\(^2\)-\(\dfrac{25}{27}\)=0
\(\left(\dfrac{1}{3}\right)^{2X-1}-\left(\dfrac{1}{3}\right)^2=-\dfrac{1}{27}\)
(2x-1)\(^3\)=\(\dfrac{-1}{27}\)
\(x^2-19=5.9;\left(2x+1\right)^3=-0,001;\left(\dfrac{5}{6}\right)^{2x-1}=\left(\dfrac{5}{6}\right)^5;\left(\dfrac{1}{3}x-\dfrac{2}{3}\right)^3=27;\left(\dfrac{1}{32}\right)^x=\left(\dfrac{1}{2}\right)^{15}\)
5$-\frac{5}{3}+\frac{5}{9}-\frac{5}{27}$ \(8-\dfrac{8}{3}+\dfrac{8}{9}-\dfrac{8}{27}\) trên nhau nha