\(\left(2x-1\right)^3=125\\ \Rightarrow2x-1=5\\ \Rightarrow2x=6\\ \Rightarrow x=3\)
(2x−1)3 = 125
⇒ 2x − 1 = 5
⇒ 2x = 6
⇒ x = 3
(2x−1)\(^3\) = 125
(2x - 1)\(^3\) = 5\(^3\)
=> 2x - 1 = 5
2x = 5 + 1
2x = 6
x = 6 : 2
x = 3
Vây x = 3
Ta có: \(\left(2x-1\right)^3=125\)
\(\Leftrightarrow2x-1=5\)
\(\Leftrightarrow2x=6\)
hay x=3